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- 3 Articles on the proof of Fermat's Last Theorem
-
- Newsweek, New York Times, and FXKMS@acad3.alaska.edu.
- =========
-
- Internet Amateur Mathematics Society
- Newsletter 5
-
- IAMS@quack.kfu.com
-
- Fermat's Last Theorem Proved
-
- If you haven't heard it yet, Dr. Andrew Wiles had claimed that he
- proved the famous Fermat's Last Theorem. Here I have three articles,
- one from Newsweek, one from New York Time, and the other one from
- FXKMS@acad3.alaska.edu.
-
-
-
- Brief Summary of Dr. Wiles' Proof, From FXKMS@acad3.alaska.edu
-
-
- If E is a semistable elliptic curve defined over Q,
- then E is modular.
-
- It has been known for some time, by work of Frey and Ribet, that
- Fermat's Theorem follows from this. If
-
- u^q + v^q + w^q = 0,
-
- then Frey had
- the idea of looking at the (semistable) elliptic curve
-
- y^2 = x(x-a^q)(x+b^q).
-
- If this elliptic curve comes from a modular form,
- then the work of Ribet on Serre's conjecture shows that there
- would have to exist a modular form of weight 2 on $\Gamma_0(2)$. But
- there are no such forms.
-
- To prove the Theorem, start with an elliptic curve $E$, a prime $p$ and let
-
- \rho_p : \Gal(\bar{Q}/Q) \to \GL_2(\Z/p\Z)
-
- be the representation giving the action of Galois on the p-torsion
- E[p]. We wish to show that a certain lift of this representation to
- GL_2(Z_p) (namely, the p-adic representation on the Tate module
- T_p(E)) is attached to a modular form. We will do this by using
- Mazur's theory of deformations, to show that every lifting which
- `looks modular' in a certain precise sense is attached to a modular
- form.
-
- Fix certain `lifting data', such as the allowed ramification,
- specified local behavior at $p$, etc. for the lift. This defines a
- lifting problem, and Mazur proves that there is a universal
- lift, i.e. a local ring R and a representation into GL_2(R) such
- that every lift of the appropriate type factors through this one.
-
- Now suppose that \rho_p is modular, ie there is some lift
- of \rho_p which is attached to a modular form. Then there is
- also a hecke ring T, which is the maximal quotient of R with the
- property that all modular lifts factor through T. It is a
- conjecture of Mazur that R = T, and it would follow from this
- that every lift of \rho_p which `looks modular' (in particular the
- one we are interested in) is attached to a modular form.
-
- Thus we need to know 2 things:
-
- 1. \rho_p is modular
- 2. R = T.
-
- It was proved by Tunnell that \rho_3 is modular for every elliptic
- curve. This is because \PGL_2(\Z/3\Z) = S_4. So (1) will be satisfied
- if we take p=3. This is crucial.
-
- Wiles uses (a) to prove (b) under some restrictions on \rho_p. Using
- (a) and some commutative algebra (using the fact that T is Gorenstein,
- `basically due to Mazur') Wiles reduces the statement T = R to
- checking an inequality between the sizes of 2 groups. One of these
- is related to the Selmer group of the symmetric sqaure of the given
- modular lifting of \rho_p, and the other is related (by work of Hida)
- to an L-value. The required inequality, which everyone presumes is
- an instance of the Bloch-Kato conjecture, is what Wiles needs to verify.
-
- He does this using a Kolyvagin-type Euler system argument. This is
- the most technically difficult part of the proof, and is responsible
- for most of the length of the manuscript. He uses modular
- units to construct what he calls a 'geometric Euler system' of
- cohomology classes. The inspiration for his construction comes
- from work of Flach, who came up with what is essentially the
- `bottom level' of this Euler system. But Wiles needed to go much
- farther than Flach did. In the end, under certain hypotheses on \rho_p
- he gets a workable Euler system and proves the desired inequality.
- Among other things, it is necessary that \rho_p is irreducible.
-
- Suppose now that E is semistable.
- There are 2 cases:
-
- 1. \rho_3 is irreducible. Take p=3. By Tunnell's theorem (a)
- above is true. Under these hypotheses the argument above works for
- \rho_3, so we conclude that E is modular.
-
- 2. \rho_3 is reducible. Take p=5. In this case \rho_5 must be
- irreducible, or else E would correspond to a rational point on
- X_0(15). But X_0(15) has only 4 noncuspidal rational points, and
- these correspond to non-semistable curves. If we knew that
- \rho_5 were modular, then the computation above would apply and E
- would be modular.
-
- We will find a new semistable elliptic curve E' such that
- \rho_{E,5} = \rho_{E',5} and \rho_{E',3} is irreducible. Then
- by Case 1, E' is modular. Therefore \rho_{E,5} = \rho_{E',5}
- does have a modular lifting and we will be done.
-
- We need to construct such an E'. Let X denote the modular
- curve whose points correspond to pairs (A, C) where A is an
- elliptic curve and C is a subgroup of A isomorphic to the group
- scheme E[5]. (All such curves will have \bmod 5 representation
- equal to \rho_E.) This X is genus 0, and has one rational point
- corresponding to E, so it has infinitely many. Now Wiles uses a
- Hilbert Irreducibility argument to show that not all rational
- points can be images of rational points on modular curves
- covering X, corresponding to degenerate level 3 structure
- (i.e. \Im(\rho_3) not \GL_2(Z/3)). In other words, an E' of the
- type we need exists. (To make sure E' is semistable, choose
- it 5-adically close to E. Then it is semistable at 5, and at
- other primes because \rho_{E',5} = \rho_{E,5}.)
-
-
-
-
- New Answer for an Old Question, The proof's in the putting
-
- By Sharon Begley with Joshua Copper Ramo
-
- Newsweek, July 5th 1993, Pg 52
- Copyright 1993 NEWSWEEK, INC.: 444 MADISON AVENUE, N.Y, N.Y, 10022 All
- Rights Reserved.
-
- "I have found a truly wonderful proof which this margin[of my
- notebook] is too small to contain." So asserted French mathematician
- Pierre de Fermat in 1637, in what became the biggest historical dare
- in mathematics. He was referring to a beguilingly simple assertion
- about numbers that had intrigued mathematicians since Roman times.
- Fermat died 18 years later, never having gotten around to writing down
- his "admirable proof". That should have been a tip-off. The greatest
- minds of the next four centuries tried to find this proof and failed
- so abysmally that Fermat's last Theorem, as the assertion was known,
- became the top unsolved challenge in all mathematics. Now it may have
- fallen. Last week, in a lecture at Cambridge University in England,
- Andrew Wiles of Princeton University announced that he had proved
- Fermat's Last. Within an hour number theorists were spreading the
- word from London to Boulder to Berkeley through a joyous hail of
- E-mail. "There is a sort of euphoria", exalted Princeton math
- department chairman Simon Kochen. "Euphoria because we lived to see
- this."
-
- Pure mathematics is a sucker's game. It lures the curious and
- confident with its seeming simplicity only to make them look like
- fools. Consider the equation 9+16=25. It can be written
- 3^2+4^2=5^2. More generally, one can write that a number squared
- (multiplied by itself) plus a second number squared equals a third
- number squared. Now the inquisitive are hooked like rubes in
- three-card monte. Try to find three whole numbers that fit the
- equation x^3+y^3=z^3. That is, pick numbers for x and y, multiply
- each by itself twice (like 3\times 3\times 3), and find a third
- number z which, when multiplied by itself twice, equals to the sum of
- the x^3 and y^3. There is no such z. That's what Fermat's Last
- states. Nor are there any numbers that fit the equation where the
- exponents are anything greater than 2. That's what Fermat claimed to
- have proved.
-
- Fermat did, in fact, prove his assertion for exponents of 4. Leonard
- Euler, the great Swiss mathematician, proved it for exponents of 3 in
- the 1790s. France's Adrien Legendre proved it for exponents of 5 in
- 1823. A few years ago a computer proved it for everything less than
- 30,000. Things were looking pretty good for Fermat's last, but none
- of this constituted a persuasive proof. What if the number right
- after the last number checked turned out to falsify the theorem? Only
- a rigorous proof would do. Their inability to find one, especially in
- the face of Fermat's taunt, drove mathematicians crazy.
-
- Too shy: Wiles approached Fermat's last Theorem the way one would a
- skittish horse -- obliquely. He started with a 1984 finding that if
- there are any numbers for which Fermat's equations holds, then the
- solutions can be fashioned into something called an elliptic curve.
- Then wiles noted a 1987 proof by Ken Ribet of the University of
- California, Berkeley, that any such elliptic curves could not be of a
- certain type. (Those who can't balance their checkbooks can drop out
- here.) When Wiles proved the contrary -- that the relevant elliptic
- curves are of this type -- he had shown the "if" he started with to be
- wrong: there are no numbers that make Fermat's equation work. Just as
- the Frenchman said 356 years ago. This all took Wiles 200 pages.
- Wiles (who describes himself as too shy to talk to the press) combined
- ideas from number theory, topology and other disparate fields and
- basically "three the kitchen sink" at Fermat's Last, says Kochen.
- "Among theorists there is often a sense that something just looks
- right. It's the general feeling that [Wiles's proof] looks right," he
- says.
-
- Mathematicians will not know for sure until they check every line, a
- process that could take years. Thousands of other claims to have
- proved Fermat's Last Theorem have fizzled. But if Wiles has triumphed
- over the historical dare, his proof would promise a huge advance in
- number theory. It is a field of almost pristine irrelevance to
- everything except the wondrous demonstration that pure numbers, no more
- substantial than Plato's shadows, conceal magical laws and orders that
- the human mind can discover after all.
-
-
-
-
- At Last, Shout of `Eureka!' In Age-Old Math Mystery
-
- By Gina Kolata
-
- The New York Times, Thursday, June 24, 1993
- Copyright 1993 The New York Times
-
- More than 350 years ago, a French mathematician wrote a deceptively
- simple theorem in the margins of a book, adding that he had discovered
- a marvelous proof of it but lacked space to include it in the margin.
- He died without ever offering his proof, and mathematicians have been
- trying eversince to supply it. Now, after thousands of claims of
- success that proved untrue, mathematicians say the daunting challenge,
- perhaps the most famous of unsolved mathematical problems, has at last
- been surmounted.
-
- The problem is known as Fermat's last theorem, and its apparent
- conqueror is Dr. Andrew Wiles, a 40-year-old English mathematician who
- works at Princeton University. Dr. Wiles announced the result
- yesterday at the last of three lectures given over three days at
- Cambridge University in England.
-
- Within a few minutes of the conclusion of his final lecture, computer
- mail messages were winging around the world as mathematicians alerted
- each other to the startling and almost wholly unexpected result.
-
- Dr. Leonard Adelman of the University of Southern California said he
- received a message about an hour after Dr. Wiles's announcement. The
- frenzy is justified, he said. "It's the most exciting thing that's
- happened in -- geez -- maybe every, in mathematics."
-
- Mathematicians present at the lecture said they felt "an elation",
- said Dr. Kenneth Ribet of the University of California at Berkeley, in
- a telephone interview from Cambridge.
-
- Impossible Is Possible
-
- The theorem, an overarching startment about what solutions are
- possible for certain simple equations, was stated in 1673 by Pierre de
- Fermat, a 17th century French mathematician and physicist. Many of
- the brightest minds in mathematics have struggled to find the proof
- ever since, and many have concluded that Fermat, contrary to his
- tantalizing claim, had probably failed to develop one despite his
- considerable mathematical ability.
-
- With Dr. Wiles' result, Dr. Ribet said, "the mathematical landscape
- has changed." He explained: "Your discover that things that seemed
- completely impossible are more of a reality. This changes the way you
- approach problems, what you think is possible."
-
- Dr. Barry Mazur, a Harvard University mathematician, also reached by
- telephone in Cambridge, said: "A lot more is proved than Fermat's last
- theorem. One could envision proof of a problem, no matter how
- celebrated, that had no implications. But this is just the reverse.
- This is the emergence of a technique that is visibly powerful. It's
- going to prove a lot more."
-
- Remember Pythagoras?
-
- Fermat's last theroem has to do with equations of the form
- x^n+y^n=z^n. The case where n is 2 is familiar as the Pythagorean
- theorem that the squares of the lengths of two sides of a right angled
- triangle equal the square of the length of the hypotenuse. One such
- equation is 3^2+4^2=5^2, since 9+16=25.
-
- Fermat's last theorem states that there are no solutions to such
- equations when n is a whole number greater than 2. This means, for
- instance, that it would be impossible to find any whole numbers x, y
- and z such that x^3+y^3=z^3. Thus 3^3+4^3, (27+64)=91, which is
- not the cube of any whole number.
-
- Mathematicians in the United States said that the stature of Dr. Wiles
- and the imprimatur of the experts who heard his lectures, especially
- Dr. Ribet and Dr. Mazur, convinced them that the new proof was very
- likely to be right. In addition, they said, the logic of the proof is
- persuasive because it is is built on a carefully developed edifice of
- mathematics that goes back more than 30 years and is well accepted by
- researchers.
-
- Experts cautioned that Dr. Wiles could of course have made some subtle
- misstep. Famous and not-so-famous mathematicians have claimed proofs
- in the past, only to be tripped up by errors. Dr. Harold M. Edwards,
- a mathematician at the Courant Institute of Mathematical Sciences in
- New York, said that until the proof was published in a mathematical
- journal, which could take a year, and until it is checked many times,
- there is always a chance it is wrong. The author of a book on
- Fermat's last theorem, Dr. Edwards noted that "even good
- mathematicians have had false proofs."
-
- Luring the World's `Cranks'
-
- But even he said that Dr. Wiles's proof sounds like the real thing and
- "has to be taken very seriously."
-
- Despite the apparent simplicity of the theorem, proving it was so hard
- that in 1815 and in again 1860, the French Academy of Science offered
- a gold medal and 300 francs to anyone who could solve it. In 1908,
- the German Academy of Science offered a prize of 100,000 marks for a
- proof that the theorem was correct. The prize, which still stands
- though has been reduced to 7,500 marks, about $4,385, has attracted
- the world's "cranks", Dr. Edwards said. When the Germans said the
- proof had to be published, "the cranks began publishing their
- solutions in the vanity press," he said, yielding thousands of
- booklets. The Germans told him they would even award the prie for a
- proof that the theorem was not true, Dr. Edwards added, saying that
- they "would be so overjoyed that they wouldn't have to read through
- these submissions."
-
- But it was not just amateurs whose iamgination was captured by the
- enigmatic problem. Famous mathematicians, too, spent years of their
- lives on it. Others chose never to get near it for fear of being
- sucked into a quagmire. One mathematical genius, David Hilbert, said
- in 1920 that he would not work on it because, "before beginning I
- should put in three years of intensive study, and I haven't that much
- time to spend on a probable failure."
-
- Mathematicians armed with computers have shown that Fermat's theorem
- holds true up to very high numbers. But that falls well short of a
- general proof.
-
- Tortuous Path to Proof
-
- Dr. Ribet said that 20th century work on the problem began to grow
- ever more divorced from Fermat's quations. "Over the last 60 years,
- people in number theory have forged an incredible number of tools to
- deal with simple problems like this," he said. "As the tools became
- more complicated, they took on a life of their own. People lost
- day-to-day contact with the old problems and were preoccupied with the
- objects they created."
-
- Dr. Wiles' proof draws on many of these mathematical tools but also
- "completes a chain of ideas," said Dr. Nicholas Katz of Princeton
- University. The work leading to the proof began in 1954, when the
- late Japanese mathematician Yutaka Taniyama made a conjecture about
- mathematical objects called elliptical curves. That conjecture was
- refined by Dr. Goro Shimura of Princeton University a few years later.
- But, Dr. Katz said, mathematicians had no perception through the
- 1950's to 70's that this had any relationship to Fermat's last
- theorem. "They seemed to be on different planets," he said.
-
- In the mid-80's, Dr. Gerhard Frey of the University of the Saarland in
- Germany "came up with a very strange, very simple connection between
- the Taniyama conjecture and Fermat' last theorem, " Dr. Katz said.
- "It gave a sort of rough idea that if you knew Taniyama conjecture you
- would in fact know Fermat's last theorem." He explained. In 1987,
- Dr. Ribet proved the connection. Now, Dr. Wiles has shown that a form
- of the Taniyama conjecture is ture and that this implies tht Fermat's
- last theorem must be true.
-
- "One of the things that's most remarkable about the fact that Fermat's
- last theorem is proven is the incredibly roundabout path that led to
- it," Dr. Katz said.
-
- Arcane to the Arcane
-
- Another remarkable aspect is that such a seemingly simple problem
- would require such sophisticated and highly specialized mathematics
- for its proof. Dr. Ribet estimated that a tenth of one percent of
- mathematicians could understand Dr. Wiles' work because the
- mathematics is so technical. "You have to know a lot about modular
- forms and algebraic geometry," he said. "You have to have ollowed the
- subject very closely."
-
- The general idea behind Dr. Wiles' rpoof was to associate an elliptic
- curve, which is a mathematical object that looks something like the
- surface of a doughnut, with an equation of Fermat's theorem. If the
- theroem were false and there were indeed solutions to the Fermat
- equations, a peculiar curve would result. The proof hinged on showing
- that such a curve could not exist.
-
- Dr. Wiles, who has told mathematicians he is reluctant to speak to the
- press, could not be reached yesterday. Dr. Ribet, who said Dr. Wiles
- was shy, said he was asked to speak for him.
-
- Dr. Ribet said it took Dr. Wiles seven years to solve the problem. He
- had a solution for a special case of the conjecture two years ago, Dr.
- Ribet said, but told no one. "It didn't give him enough and he felt
- very discouraged by it", he said.
-
- Dr. Wiles presented his results this week at a small conference in
- Cambridge, England, his birthplace, on "Padic Galois Representations,
- Iwasawa Theory and the Tamagawa Numbers of Motives." He gave a
- lecture a day on Monday, Tuesday and Wednesday with the title "Modular
- Forms, Elliptic Curves and Galois Representations." There was no hint
- in the title that Fermat's last theroem would be discussed, Dr. Ribet
- said.
-
- "As Wiles began his lectures, thee was more and more speculation about
- what it was going to be, " Dr. Ribet said. The audience of
- specialists in these arcane fields swelled from about 40 on the first
- day to 60 yesterday. Finally, at the end of his third lecture, Dr.
- Wiles concluded that he had proved a general case of the Tatiyama
- cnjecture. Then, seemingly as an after thought, he noted that that
- meant that Fermat;s last theorem was true. Q.E.D.
-
- People raised their cameras and snapped pictures of this historic
- moment, Dr. Ribet said. Then "there was a warm round of applause,
- followed by a couple of questions and another warm round of applause,"
- he added.
-
- "I had to give the next lecture, " Dr. Ribet said. "It was something
- incredibly mundane." Since mathematicians are "a pretty well behaved
- bunch," they listened politely. But, he said, it was hard to
- concentrate. "Most people in the room, including me, were incredibly
- shell-shocked," he said.